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A projectile with mass m is launched into the air on a parabolic trajectory. For t ≥0, its horizontal and vertical coordinates are x(t)=u0 t and y(t)=-(1)/(2) g t^2 v0 t, respectively, where u0 is the initial horizontal velocity, v0 is the initial vertical velocity, and g is the acceleration due to gravity. Recalling that u(t)=x^'(t) and v(t)=y^'(t) are the components of the velocity, the energy of the projectile (kinetic plus potential) is E(t)=(1)/(2) m(u^2 v^2) m g y Use the Chain Rule to com
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